POLOŽAJ BRODA SA ZVJEZDOM, NEPOZNATOM ZVJEZDOM I PLANETOM POLOŽAJ BRODA SA DVIJE ZVJEZDE – DIREKTNA METODA (DOSSIEROVA) Dana ............................................................. Osmatrana su nebeska tijela kako slijedi: 1. ............................ ..Tk:.................................... Vop= .................................... 2. ............................. Tk ................................... Vop= ................................... Vis.oka: .................. Ki: ........................ Ke: ....................St.k: ........................... φz= ...................................... λz= ................................... Vrijeme Neb.tijelo 1 Neb.tijelo 2 Tk =.............................. +St.k.= ........................... UTC= .......................... Tk =.............................. +St.k.= ........................... UTC= .......................... Visina prava Visina prava Vs1= ................................ +Ki= ............................... +Ke= ............................... + dep= .............................. VPRIV= .............................. +Kor = ………………… Vs2= ................................ +Ki= ............................... +Ke= ............................... + dep = ............................... VPRIV= ............................... +Kor = …………………… Vp1 = Vp2 = Satni kut Sy= .......................................... +Kor= ........................................ =Sy= .......................................... + (360-α)=................................... =Sy= ........................................... =Sy= ......................................... δ= .............................. Sy= ............................................. +Kor= .......................................... =Sy= ............................................ + (360-α)=...................................... =Sy= ............................................... =Sy= .......................................... δ= .............................. Računamo udaljenost između zvijezda sa deltom satnog kuta po formuli: ΔS=S2 – S1 ili ( S1 – S2 )…………………… koji je veći ΔS=................................ – ................................. ΔS= ............................................................................. Cos D = ( Sin δ1 x Sinδ2 ) + ( Cos δ2 x Cosδ2 x Cos ΔS) Cos D = ( Sin ..................*Sin ...................)+( Cos ..................*Cos ....................* Cos .....................) D = ...................................... Sad računamo paralaktičke kutove α, β, Cos α = = Kut α = ................ Cos β = = Cos β = ................. Treći kut se dobije sa (y = α - β) ili (y = α + β) Geografsku širinu računamo sa trećim kutem iz formule: Sinφp = Sinδ2 x SinVp2 + ( Cosδ2 x CosVp2 x Cos y ) Sinφp = (Sin ..................... x Sin ...........................) + ( Cos ................... x Cos ..................... x Cos ............................... ) φp = ....................................... ( Ako širina prava nije blizu procjenjene računa se sa drugom kombinacijom (α +β)) Sinφp = (Sin ................... x Sin ........................) + ( Cos ................... x Cos ........................... x Cos ......................... ) φp = .................................................. Geografsku dužinu računamo iz formule a koristimo drugu zvijezdu. Cos s = = s*2 = ............................................... s*2 = ............................................. (Mjesni satni kut) -S*2 = .............................................. (Satni kut u Griniču) λ = ................................................ λ = ................................................ Pp = Računskim putem pozicija prava. Δφ= = Δλ= = φ1=.......................... λ1= ......................... + Δφ= ±....................... +Δλ= ±...................... φP= ......................... λP= ....................... _72100588.unknown _1211734182.unknown _1211734207.unknown _72100917.unknown _1211733159.unknown _72100810.unknown _72100522.unknown _72100550.unknown _72100487.unknown _72099979.unknown